The reaction
`2A(g)+B(g)hArr 3C(g)+D(g)`
is begun with the concentrations of A and B both at an intial value of 1.00 M. When equilibrium is reached, the concentration of D is measured and found to be 0.25 M. The value for the equilibrium constant for this reaction is given by the expression.

Options

A. `[(0.75)^3(0.25)] div [(1.00)^2(1.00)]`
B. `[(0.75)^3(0.25)] div [(0.50)^2(0.75)]`
C. `[(0.75)^3(0.25)]div[(0.50)^2(0.25)]`
D. `[(0.75)^3(0.25)] div [(0.75)^2(0.25)]`

Answer

B