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The dissociation constant of a weak acid...

The dissociation constant of a weak acid is `1 xx 10^(-4)`. In order of prepare a buffer solution with a pH =5 the [Salt]/[Acid] ratio should be

A

`1:10`

B

`4:5`

C

`10:1`

D

`5:4`

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The correct Answer is:
To find the ratio of salt to acid in a buffer solution with a given pH, we can use the Henderson-Hasselbalch equation, which relates pH, pKa, and the concentrations of the acid and its salt. ### Step-by-step Solution: 1. **Identify the given values**: - Dissociation constant (Ka) of the weak acid = \(1 \times 10^{-4}\) - Desired pH of the buffer solution = 5 2. **Calculate pKa**: - The relationship between Ka and pKa is given by: \[ pKa = -\log(Ka) \] - Substituting the value of Ka: \[ pKa = -\log(1 \times 10^{-4}) = 4 \] 3. **Use the Henderson-Hasselbalch equation**: - The equation is: \[ pH = pKa + \log\left(\frac{[Salt]}{[Acid]}\right) \] - Substituting the known values: \[ 5 = 4 + \log\left(\frac{[Salt]}{[Acid]}\right) \] 4. **Rearrange the equation to find the log ratio**: - Subtract pKa from both sides: \[ 5 - 4 = \log\left(\frac{[Salt]}{[Acid]}\right) \] - This simplifies to: \[ 1 = \log\left(\frac{[Salt]}{[Acid]}\right) \] 5. **Convert the log ratio to a regular ratio**: - To eliminate the logarithm, we exponentiate both sides: \[ \frac{[Salt]}{[Acid]} = 10^1 = 10 \] 6. **Express the ratio**: - The ratio of salt to acid is: \[ \frac{[Salt]}{[Acid]} = 10:1 \] ### Final Answer: The ratio of salt to acid should be \(10:1\). ---
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