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In HS^(-), I^(-), R-NH(2), NH(3) order o...

In `HS^(-)`, `I^(-)`, `R-NH_(2)`, `NH_(3)` order of proton accepting tendency will be

A

`I^- gt NH_3 gt R -NH_2 gt HS^-`

B

`NH_3 gt R -NH_2 gt HS^- gt I^-`

C

`R-NH_2 gt NH_3 gt HS^- gt I^-`

D

`HS^- gt R-NH_2 gt NH_3 gt I^-`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of proton-accepting tendency (basicity) for the species HS^(-), I^(-), R-NH2, and NH3, we can analyze their basic properties step by step. ### Step 1: Understand Basicity Basicity refers to the ability of a species to accept protons (H^+ ions). The stronger the base, the more readily it will accept a proton. ### Step 2: Compare R-NH2 and NH3 - **R-NH2 (Alkylamine)**: This is a strong base due to the +I (inductive) effect of the alkyl group (R). The alkyl group donates electron density to the nitrogen atom, making it more capable of accepting a proton. - **NH3 (Ammonia)**: Ammonia is a weaker base compared to R-NH2 because it lacks the electron-donating alkyl group. **Conclusion for Step 2**: R-NH2 > NH3 in terms of basicity. ### Step 3: Compare HS^(-) and I^(-) - **HS^(-) (Hydrosulfide ion)**: This is the conjugate base of H2S, which is a weak acid. Therefore, HS^(-) is a relatively stronger base. - **I^(-) (Iodide ion)**: This is the conjugate base of HI, which is a strong acid. The stronger the acid, the weaker its conjugate base. Therefore, I^(-) is a weak base. **Conclusion for Step 3**: HS^(-) > I^(-) in terms of basicity. ### Step 4: Combine the Results Now we can combine our findings: 1. R-NH2 is the strongest base. 2. NH3 is the next strongest base. 3. HS^(-) follows NH3. 4. I^(-) is the weakest base. ### Final Order of Proton-Accepting Tendency The order of proton-accepting tendency (basicity) is: **R-NH2 > NH3 > HS^(-) > I^(-)**
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