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A : H3O^+ ion from water is also taken ...

A : `H_3O^+` ion from water is also taken in consideration while calculating the pH of very dilute solution (say concentration = `10^(-9)` M ) of acid
R: `[H_3O^+]` from water is only available in very dilute solution of acid.

A

If both Assertion & Reason are true and the reason in the corret explanation of the assertion, then mark

B

If both assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark

C

If Assertion is true statement but Reason is false then mark

D

If both Assertion and Reason are false statements , then mark

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion (A) and the reason (R) provided in the statement. ### Step 1: Understand the Assertion (A) The assertion states that the `H3O^+` ion from water is also taken into consideration while calculating the pH of a very dilute solution (like `10^(-9)` M) of acid. **Hint:** Think about how pH is calculated and the role of water in contributing to `H3O^+` concentration. ### Step 2: Understand the Reason (R) The reason states that `[H3O^+]` from water is only available in very dilute solutions of acid. **Hint:** Consider whether the contribution of water to `H3O^+` concentration is limited to only very dilute solutions or if it applies to all solutions. ### Step 3: Analyze the Concentration of `H3O^+` In a neutral solution, the concentration of `H3O^+` from water is `10^(-7)` M at 25°C. When you have a very dilute acid solution (like `10^(-9)` M), the concentration of `H3O^+` from the acid is less than that from water. Therefore, the total concentration of `H3O^+` ions must include both contributions. **Hint:** Calculate the total `H3O^+` concentration when the acid concentration is very low. ### Step 4: Calculate Total `H3O^+` Concentration In a `10^(-9)` M acid solution: - From the acid: `10^(-9)` M - From water: `10^(-7)` M Total `[H3O^+]` = `10^(-9) + 10^(-7) = 1.01 × 10^(-7)` M **Hint:** Remember to add the contributions from both sources to find the total `H3O^+` concentration. ### Step 5: Calculate the pH Using the total concentration of `H3O^+`, we can calculate the pH: - pH = `-log(1.01 × 10^(-7))` - pH ≈ 6.99 **Hint:** Use the logarithmic formula for pH calculation. ### Step 6: Evaluate the Truth of Assertion and Reason - The assertion (A) is **true** because we do consider `H3O^+` from water in very dilute solutions. - The reason (R) is **false** because `H3O^+` from water is present in all solutions, not just very dilute ones. **Hint:** Determine the truth values of both statements to conclude. ### Conclusion The assertion is true, and the reason is false. Therefore, the correct answer is C.
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