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The half cell reactions with reduction p...

The half cell reactions with reduction potentials are
`Pb(s) to Pb^(+2) (aq), E_("red")^(@) =-0.13 V`
`Ag(s) to Ag^(+) (aq) , E_("rod")^(@) =+0.80 V`
Calculate its emf.

Text Solution

Verified by Experts

`E_(cell)^(@)=E_("cathode")^(@)-E_("anode")^(@)`
In given reaction silver (Ag) is reduced and lead (Pb) is oxidised. So,
`E_(cell)^(@)=0.80-(-0.13)`
`" "=0.93V`
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