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Iron oxide has formula Fe"0.94"O. What f...

Iron oxide has formula `Fe_"0.94"O.` What fraction of Fe exists as `Fe^(+3)` ?

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Let there are 100 oxide ions and 94 iron ions.
`Fe^(+x):O^(-2) " "` Total negative charge on 100 Oxide `=-200`
= 94 : 100
It means as per the concept of charge neutrallity, 94 iron ions should have total charge of `+ 200`. Let number of `Fe^(+3)=x`
`therefore` Number of `Fe^(+2)=(94-x)`
Total positive charge `= 3x+2(94 - x)=200`.
On solving, x = 12
`therefore % Fe^(+3)=(12)/(94)xx 100=12.8 %`
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