When NaCl is dopped with `10^(-5) "mole % of" SrCl_(2)`, what is the no. of cationic vacanies?

Explanation

To find the number of cationic vacancies when NaCl is doped with \(10^{-5}\) mole % of SrCl\(_2\), we can follow these steps:

### Step 1: Understand the Doping Process
When SrCl\(_2\) is added to NaCl, Sr\(^{2+}\) ions replace Na\(^+\) ions in the crystal lattice. Since Sr\(^{2+}\) has a +2 charge, it will replace two Na\(^+\) ions. However, for every Sr\(^{2+}\) ion that replaces Na\(^+\), one Na\(^+\) ion will be replaced and one cationic vacancy will be created.

### Step 2: Calculate the Amount of SrCl\(_2\) Added
Given that we have \(10^{-5}\) mole % of SrCl\(_2\), we can convert this to moles.

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