An element occurs in bcc structure with cell edge 288 pm. Its density is 7.2 g `cm^(-3)`. Calculate the atomic mass of the element.

Explanation

For bcc, Z = 2 `" " A =(rho xx N_(0)xx a^(3))/(Z)`
`a=(288xx10^(-10))cm`
`rho = 7.2 g//cm^(3) " " A = (7.2xx6.02xx10^(23)xx(288xx10^(-10))^(3))/(2)`
A = 52 g/mol.