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In a face centred cubic arrangement of A...

In a face centred cubic arrangement of A and B atoms whose A atoms are at the corner of the unit cell and B atoms at the face centres. Once of the A atom is missing from one corner in unit cell. The simplest formula of compound is

A

`A_(7)B_(3)`

B

`AB_(3)`

C

`A_(7)B_(24)`

D

`A_(7//8)B_(3)`

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The correct Answer is:
To determine the simplest formula of the compound formed by A and B atoms in a face-centered cubic arrangement, we will follow these steps: ### Step 1: Identify the positions of A and B atoms - A atoms are located at the corners of the unit cell. - B atoms are located at the face centers of the unit cell. ### Step 2: Count the number of A atoms - In a face-centered cubic (FCC) unit cell, there are 8 corners. - Normally, there would be 8 A atoms (1 A atom at each corner). - However, one A atom is missing from one corner, so we have: \[ \text{Number of A atoms} = 8 - 1 = 7 \text{ A atoms} \] ### Step 3: Calculate the effective contribution of A atoms - Each corner atom contributes \(\frac{1}{8}\) of an atom to the unit cell because it is shared among 8 unit cells. - Therefore, the effective number of A atoms in the unit cell is: \[ \text{Effective A atoms} = 7 \times \frac{1}{8} = \frac{7}{8} \text{ A atoms} \] ### Step 4: Count the number of B atoms - There are 6 face centers in the unit cell. - Each face-centered atom contributes \(\frac{1}{2}\) of an atom to the unit cell because it is shared between 2 unit cells. - Therefore, the effective number of B atoms in the unit cell is: \[ \text{Effective B atoms} = 6 \times \frac{1}{2} = 3 \text{ B atoms} \] ### Step 5: Write the formula based on the effective number of atoms - We have: \[ \text{A} = \frac{7}{8}, \quad \text{B} = 3 \] - The formula can be written as: \[ \text{A}_{\frac{7}{8}} \text{B}_{3} \] ### Step 6: Convert to simplest integer form - To convert the formula to integer form, we multiply both the number of A and B atoms by 8 (the denominator of A): \[ \text{A} = 7, \quad \text{B} = 3 \times 8 = 24 \] - Thus, the simplest formula of the compound is: \[ \text{A}_7 \text{B}_{24} \] ### Conclusion The simplest formula of the compound is \(\text{A}_7 \text{B}_{24}\). ---
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AAKASH INSTITUTE ENGLISH-THE SOLID STATE -Assignment (SECTION - A) (OBJECTIVE TYPE QUESTION)
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  4. In any ionic crystal A has formed cubical close packing and B atoms ar...

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  5. A binary solid A^(+)B^(-) has a structure with B^(-) ions constituting...

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  6. In a crystalline solid, anion B are arranged in cubic close packing an...

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  7. In a cubic close packed structure of mixed oxides, the lattice is made...

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  8. Titanium crystallizes in a face centred cubic lattice. It reacts with ...

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  9. The site labelled as 'X' in fcc arrangement is

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  10. A unit cell is obtained by closed packing layers of atoms in ABAB …… p...

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  11. In certain solid, the oxide ions are arranged in ccp. Cations A occupy...

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  12. A solid has a structure in which A atoms are located at the cube corne...

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  13. If a is the length of unit cell, then which one is correct relationshi...

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  14. For face centered cubic structure edge length 'a' can be related with ...

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  15. A crystalline solid AB adopts sodium chloride type structure with edge...

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  16. If radius of an octahedral void is r and atomic radius of atoms assumi...

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  18. CsCl has bcc structure with Cs^(+) at the centre and Cl^(-) ion at eac...

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  19. Ice crystallises in hexagonal lattice having volume of unit cell is 13...

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  20. For tetrahedral co-ordination the radius ratio (r^(+) //r^(-))should b...

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