Home
Class 12
CHEMISTRY
Titanium crystallizes in a face centred ...

Titanium crystallizes in a face centred cubic lattice. It reacts with carbon or hydrogen interstitially by allowing atoms of these elements to occupy holes in the host lattice. Hydrogen occupies tetrahedral holes but carbon occupies octahedral holes the formula of titanium carbide and hydride are

A

`TiC_(2), TiH_(4)`

B

`TiC, TiH_(2)`

C

`Ti_(3)C, TiH_(2)`

D

`TiC_(2), TiH`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the formulas of titanium carbide and titanium hydride, we need to analyze the face-centered cubic (FCC) lattice of titanium and the positions of carbon and hydrogen in the lattice. ### Step-by-Step Solution: 1. **Understanding the FCC Lattice**: - Titanium crystallizes in a face-centered cubic (FCC) lattice. - In an FCC unit cell, there are: - 8 corner atoms, each shared by 8 unit cells (contributing \( \frac{1}{8} \times 8 = 1 \) atom). - 6 face-centered atoms, each shared by 2 unit cells (contributing \( \frac{1}{2} \times 6 = 3 \) atoms). - Therefore, the total number of titanium atoms per unit cell is: \[ 1 + 3 = 4 \text{ titanium atoms} \] 2. **Calculating Tetrahedral and Octahedral Voids**: - In an FCC lattice, the number of tetrahedral voids is twice the number of atoms per unit cell: \[ \text{Number of tetrahedral voids} = 2 \times 4 = 8 \] - The number of octahedral voids is equal to the number of atoms per unit cell: \[ \text{Number of octahedral voids} = 4 \] 3. **Determining the Formula for Titanium Carbide (TiC)**: - Carbon occupies the octahedral voids. Since there are 4 octahedral voids, we can place 4 carbon atoms in these voids. - The ratio of titanium to carbon in the unit cell is: \[ \text{Ti: C} = 4:4 = 1:1 \] - Therefore, the formula for titanium carbide is: \[ \text{TiC} \] 4. **Determining the Formula for Titanium Hydride (TiH₂)**: - Hydrogen occupies the tetrahedral voids. Since there are 8 tetrahedral voids, we can place 8 hydrogen atoms in these voids. - The ratio of titanium to hydrogen in the unit cell is: \[ \text{Ti: H} = 4:8 = 1:2 \] - Therefore, the formula for titanium hydride is: \[ \text{TiH}_2 \] ### Final Formulas: - The formula for titanium carbide (TiC) is **TiC**. - The formula for titanium hydride (TiH₂) is **TiH₂**.
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION - B) (OBJECTIVE TYPE QUESTION)|25 Videos
  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION - C) (PREVIOUS YEARS QUESTION)|41 Videos
  • THE SOLID STATE

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|30 Videos
  • THE S-BLOCK ELEMENTS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-J)|10 Videos
  • THERMODYNAMICS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (Section -D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

An element crystallizes in face centred cubic lattice. Calculate the length of the side of the unit cell if the radius of atom is 200 pm.

An element crystallises in a face -centred cubic (fcc) unit cell with cell edge a. The distance between the centre of two nearest octahedral voids in the crystal lattice is ::

A forms ccp lattice B occupy half of the octahedral voids and O occupy all the tetrahedral voids. Calculate formula-

A substance A_(x)B_(y) crystallizes in a face-centred cubic lattice in which atoms A occupy the centres of each face of the cube and B occupy each corner of the cube. Identify the correct composition of the substane

A substance A_(x)B_(y) crystallizes in a face-centred cubic lattice in which atoms A occupy the centres of each face of the cube. Identify the correct composition of the substance A_(x)B_(y) .

Arrange simple cubic, body centred cubic and face cented cubic lattic in increasing order of the fraction of the occupied space.

Atoms of elements B from hcp lattice and those of element A occupy two-thirds of tetrahedral voids. What is the formula of the compound formed by elements A and B ?

The lattice points of a crystal of hydrogen iodide are occupied by :

In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centred positions. If one atom of B is missin from one of the face centred points,, the formula of the compound is :

In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centred positions. If two atom of B is missin from two of the face centred points,, the formula of the compound is :

AAKASH INSTITUTE ENGLISH-THE SOLID STATE -Assignment (SECTION - A) (OBJECTIVE TYPE QUESTION)
  1. In a crystalline solid, anion B are arranged in cubic close packing an...

    Text Solution

    |

  2. In a cubic close packed structure of mixed oxides, the lattice is made...

    Text Solution

    |

  3. Titanium crystallizes in a face centred cubic lattice. It reacts with ...

    Text Solution

    |

  4. The site labelled as 'X' in fcc arrangement is

    Text Solution

    |

  5. A unit cell is obtained by closed packing layers of atoms in ABAB …… p...

    Text Solution

    |

  6. In certain solid, the oxide ions are arranged in ccp. Cations A occupy...

    Text Solution

    |

  7. A solid has a structure in which A atoms are located at the cube corne...

    Text Solution

    |

  8. If a is the length of unit cell, then which one is correct relationshi...

    Text Solution

    |

  9. For face centered cubic structure edge length 'a' can be related with ...

    Text Solution

    |

  10. A crystalline solid AB adopts sodium chloride type structure with edge...

    Text Solution

    |

  11. If radius of an octahedral void is r and atomic radius of atoms assumi...

    Text Solution

    |

  12. Polonium adopts cubic structure with edge length of cube being 0.336 n...

    Text Solution

    |

  13. CsCl has bcc structure with Cs^(+) at the centre and Cl^(-) ion at eac...

    Text Solution

    |

  14. Ice crystallises in hexagonal lattice having volume of unit cell is 13...

    Text Solution

    |

  15. For tetrahedral co-ordination the radius ratio (r^(+) //r^(-))should b...

    Text Solution

    |

  16. The radius of Na^+ ion is 95 pm and that of Cl^- ion is 181 pm. Predic...

    Text Solution

    |

  17. Lithium metal has a body centred cubic structure. Its density is 0.53g...

    Text Solution

    |

  18. What is the volume of a face centred cubic unit cell, when its density...

    Text Solution

    |

  19. The number of octahedral sites in a cubical close pack array of N sphe...

    Text Solution

    |

  20. For a solid with the following structure, the coordination number of t...

    Text Solution

    |