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0.1 M aqueous solution of K4[Fe(CN)6] wi...

0.1 M aqueous solution of `K_4[Fe(CN)_6]` will have the same freezing point as 0.1 M aqueous solution of

A

`Fe(SO_4)_3`

B

`Al_2(SO_4)_3`

C

`AlCl_3`

D

`K_3PO_4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to determine which 0.1 M aqueous solution will have the same freezing point as a 0.1 M aqueous solution of \( K_4[Fe(CN)_6] \). ### Step-by-Step Solution: 1. **Understanding Freezing Point Depression**: The freezing point depression (\( \Delta T_F \)) is given by the formula: \[ \Delta T_F = i \cdot K_F \cdot m \] where: - \( i \) = van 't Hoff factor (number of particles the solute dissociates into) - \( K_F \) = freezing point depression constant (depends on the solvent) - \( m \) = molality of the solution (in this case, we are given molarity, which is the same for comparison) 2. **Determine the van 't Hoff Factor for \( K_4[Fe(CN)_6] \)**: The compound \( K_4[Fe(CN)_6] \) dissociates in solution as follows: \[ K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-} \] This results in a total of 5 particles (4 potassium ions and 1 hexacyanoferrate ion). Therefore, the van 't Hoff factor \( i \) for \( K_4[Fe(CN)_6] \) is: \[ i = 5 \] 3. **Finding a Compound with the Same van 't Hoff Factor**: We need to find another compound that also dissociates into 5 particles when dissolved in water. - **Option 1: \( FeSO_4 \cdot 3H_2O \)**: \[ FeSO_4 \cdot 3H_2O \rightarrow Fe^{2+} + SO_4^{2-} \] This gives us 2 particles, so \( i = 2 \). - **Option 2: \( Al_2(SO_4)_3 \)**: \[ Al_2(SO_4)_3 \rightarrow 2Al^{3+} + 3SO_4^{2-} \] This gives us a total of 5 particles (2 aluminum ions and 3 sulfate ions), so \( i = 5 \). - **Option 3: \( AlCl_3 \)**: \[ AlCl_3 \rightarrow Al^{3+} + 3Cl^{-} \] This gives us a total of 4 particles, so \( i = 4 \). - **Option 4: \( K_3PO_4 \)**: \[ K_3PO_4 \rightarrow 3K^+ + PO_4^{3-} \] This gives us a total of 4 particles, so \( i = 4 \). 4. **Conclusion**: The only compound that has the same van 't Hoff factor \( i = 5 \) as \( K_4[Fe(CN)_6] \) is \( Al_2(SO_4)_3 \). Thus, a 0.1 M aqueous solution of \( Al_2(SO_4)_3 \) will have the same freezing point as a 0.1 M aqueous solution of \( K_4[Fe(CN)_6] \). ### Final Answer: 0.1 M aqueous solution of \( Al_2(SO_4)_3 \) will have the same freezing point as 0.1 M aqueous solution of \( K_4[Fe(CN)_6] \). ---
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