How many coulombs of electricity are c onsumed when a 100mA current is passed through a solution of `AgNO_(3)` for half an hour during an electrolysis experiment?

Options

A. 108C
B. 180C
C. 1800C
D. 18,000C

Answer

To find out how many coulombs of electricity are consumed when a 100 mA current is passed through a solution of AgNO₃ for half an hour, we can use the formula for charge (Q):

\[ Q = I \times T \]

where:
- \( Q \) is the charge in coulombs,
- \( I \) is the current in amperes,
- \( T \) is the time in seconds.

### Step 1: Convert the current from milliamperes to amperes
Given:
- Current \( I = 100 \, \text{mA} \)

To convert milliamperes to amperes:
\[ I = 100 \, \text{mA} = 100 \times 10^{-3} \, \text{A} = 0.1 \, \text{A} \]

### Step 2: Convert the time from hours to seconds
Given:
- Time = half an hour

To convert hours to seconds:
\[ T = \frac{1}{2} \, \text{hour} = \frac{1}{2} \times 60 \times 60 \, \text{seconds} \]
\[ T = 0.5 \times 3600 \, \text{s} = 1800 \, \text{s} \]

### Step 3: Calculate the charge using the formula
Now, substituting the values of \( I \) and \( T \) into the charge formula:
\[ Q = I \times T \]
\[ Q = 0.1 \, \text{A} \times 1800 \, \text{s} \]
\[ Q = 180 \, \text{C} \]

### Conclusion
The total charge consumed when a 100 mA current is passed through a solution of AgNO₃ for half an hour is **180 coulombs**.