The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)

Options

A. `6 xx 10^(23)`
B. `6 xx 10^(20)`
C. `3.75 xx 10^(20)`
D. `7.48 xx 10^(23)`

Answer

To solve the problem of finding the number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values:**
- Current (I) = 1 ampere
- Time (T) = 60 seconds
- Charge on an electron (e) = \( 1.60 \times 10^{-19} \) coulombs

2. **Calculate the total charge (Q) delivered during the time period:**
\[ Q = I \times T \]
Substituting the values:
\[ Q = 1 \, \text{A} \times 60 \, \text{s} = 60 \, \text{C} \]

3. **Use the relationship between charge and the number of electrons:**
The total charge (Q) can also be expressed in terms of the number of electrons (n) and the charge of a single electron (e):
\[ Q = n \times e \]
Rearranging this gives:
\[ n = \frac{Q}{e} \]

4. **Substitute the values into the equation:**
\[ n = \frac{60 \, \text{C}}{1.60 \times 10^{-19} \, \text{C/electron}} \]

5. **Perform the calculation:**
\[ n = \frac{60}{1.60 \times 10^{-19}} = \frac{60}{1.6} \times 10^{19} = 37.5 \times 10^{19} \]
\[ n = 3.75 \times 10^{20} \]

6. **Conclusion:**
The number of electrons delivered at the cathode during electrolysis is \( 3.75 \times 10^{20} \).

### Final Answer:
The number of electrons delivered at the cathode is \( 3.75 \times 10^{20} \).

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