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The efficiency of a fuel cell is given b...

The efficiency of a fuel cell is given by:

A

`(Delta S)/(Delta G)`

B

`(Delta H)/(Delta G)`

C

`(Delta G)/(Delta S)`

D

`(DeltaG)/(Delta H)`

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To determine the efficiency of a fuel cell, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Fuel Cells**: - A fuel cell is a device that converts chemical energy directly into electrical energy through electrochemical reactions. It typically involves the reaction of hydrogen and oxygen to produce water and electricity. 2. **Key Terms**: - **ΔG (Gibbs Free Energy)**: This represents the maximum reversible work that can be performed by a thermodynamic system at constant temperature and pressure. - **ΔH (Change in Enthalpy)**: This represents the total heat content of the system, which includes internal energy and the energy required to displace its environment. 3. **Efficiency Formula**: - The efficiency of a fuel cell can be expressed in terms of Gibbs free energy and enthalpy. The formula is given by: \[ \text{Efficiency} = \frac{\Delta G}{\Delta H} \times 100 \] 4. **Identifying the Correct Option**: - From the options provided, we need to identify which one matches our derived formula for efficiency. The options were: 1. ΔS / ΔG 2. ΔH / ΔG 3. ΔG / ΔS 4. ΔG / ΔH - The correct option that matches our derived formula is **Option 4: ΔG / ΔH**. 5. **Conclusion**: - Therefore, the efficiency of a fuel cell is given by the ratio of Gibbs free energy change to the change in enthalpy, expressed as: \[ \text{Efficiency} = \frac{\Delta G}{\Delta H} \times 100 \]
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A fuel cell is a cell that is continously supplied with an oxidant and a reductant so that if can deliver a current indefinitely. Fuel cells offer the possibility of achieving high thermodynamic efficiency in the conversion of Gibbs energy into mechanical work.Internal combustion engines at best convert only the fraction (T_2-T_1)//T_2 of the heat of combustion into mechanical work. While the thermodynamic efficiency of the fuel cell is given by, eta=(DeltaG)/(DeltaH) , where DeltaG is the Gibbs energy change for the cell reaction and DeltaH is the enthalpy change of the cell reaction.A hydrogen-oxygen fuel cell may have an acidic or alkaline electrolyte. Pt|H_2(g)|H^(+)(aq.)||H_2O(l)|O_(2)(g)|Pt , (2.303 RT)/F=0.06 The above fuel cell is used to produce constant current supply under constant temperature & 30 atm constant total pressure conditions in a cylinder.If 10 moles H_2 and 5 moles of O_2 were taken initially. Rate of consumption of O_2 is 10 milli moles per minute. The half-cell reactions are 1/2O_2(g)+2H^+(aq)+2e^(-)toH_2O(l) E^(@)=1.246 V 2H^+(aq)+2e^(-) to H_2(g) E^(@)=0 To maximize the power per unit mass of an electrochemical cell, the electronic and electrolytic resistances of the cell must be minimized.Since fused salts have lower electolytic resistances than aqueous solutions, high-temperature electrochemical cells are of special interest for practical applications. Calculate e.m.f of the given cell at t=0.(log 2=0.3)

Thermodynamic efficiency of a cell is given by:

The thermodynamic efficiency of cell is given by

The efficiency of a fuel cell si 80% and the standard heat of reaction is -300kJ . The reaction involves two electrons in redox change. E^(c-) for the cell is (a) 1.24V (b) 2.48V (c) 0V (d) 0.62V

What is the efficiency of a fuel cell? What is the use of fuel cell ?

In a fuel cell methanol is used as fuel and oxygen gas is used as an oxidizer. The reaction is : CH_(3)OH_((l))+(3)/(2)O_(2(g))rarr CO_2((g))+2H_(2)O_((l)) At 298K standard Gibb's energies of formation for CH_(3)OH(l), H_(2)O(l) and CO_(2)(g) are -166.2,-237.2 and -394.4kJ mol^(-1) respectively. If standard enthalpy of combustion of methanol is -726kJ mol^(-1) , efficiency of the fuel cell will be :

In a fuel cell methanol is used as fuel and oxygen gas is used as an oxidizer. The reaction is : CH_(3)OH_((l))+(3)/(2)O_(2(g))rarr CO_2((g))+2H_(2)O_((l)) At 298K standard Gibb's energies of formation for CH_(3)OH(l), H_(2)O(l) and CO_(2)(g) are -166.2,-237.2 and -394.4kJ mol^(-1) respectively. If standard enthalpy of combustion of methanol is -726kJ mol^(-1) , efficiency of the fuel cell will be :

In a fuel cell methanol is used as fuel and oxygen gas is used as an oxidizer. The reaction is : CH_(3)OH_((l))+(3)/(2)O_(2(g))rarr CO_2((g))+2H_(2)O_((l)) At 298K standard Gibb's energies of formation for CH_(3)OH(l), H_(2)O(l) and CO_(2)(g) are -166.2,-237.2 and -394.4kJ mol^(-1) respectively. If standard enthalpy of combustion of methanol is -726kJ mol^(-1) , efficiency of the fuel cell will be :

In a fuel cell methanol is used as fuel and oxygen gas is used as an oxidizer. The reaction is : CH_(3)OH_((l))+(3)/(2)O_(2(g))rarr CO_2((g))+2H_(2)O_((l)) At 298K standard Gibb's energies of formation for CH_(3)OH(l), H_(2)O(l) and CO_(2)(g) are -166.2,-237.2 and -394.4kJ mol^(-1) respectively. If standard enthalpy of combustion of methanol is -726kJ mol^(-1) , efficiency of the fuel cell will be :

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