Home
Class 12
CHEMISTRY
A solution contains Fe^(2+), Fe^(3+) " a...

A solution contains `Fe^(2+), Fe^(3+) " and " I^(-)` ions. This solution was treated with iodine at `35^(@)C. E^(@)" for "Fe^(3+)//Fe^(2+)` is +0.77 V and `E^(@)" for "l_(2)//2l^(-)=`0.536 V. The favourable redox reaction is

A

`l^(-)` will be oxidised to `l_(2)`

B

`Fe^(2+)` will be oxidised to `Fe^(3+)`

C

`l_(2)` will be reudced to `l^(-)`

D

There will be no redox reaction

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

A solution contains Fe^(2+), Fe^(3+) and T^(-) ions. This solution was treated with iodine at 35^(@)C. E^(@) for Fe^(3+), Fe^(2+) is 0.77 V and E^(@) for I_(2)//2I^(-) = 0.536 V. The favourable redox reaction is:

A solution contains Fe^(2+), Fe^(3+) and T^(-) ions. This solution was treated with iodine at 35^(@)C. E^(@) for Fe^(3+), Fe^(2+) is 0.77 V and E^(@) for I_(2)//2I^(-) = 0.536 V. The favourable redox reaction is:

A solution contains Cr^(+2),Cr^(+3) and I^(-) ions, This solution was treated with iodine at 35^(@)C.E^(@) for cr^(+3)//Cr^(+2) is -0.41V and E^(@) for I_(2)//2I^(-)=0.536V , The favourable redox reaction is :-

E^(@) of Fe^(2 +) //Fe = - 0.44 V, E^(@) of Cu //Cu^(2+) = -0.34 V . Then in the cell

E^(o) for the reaction Fe + Zn^(2+) rarr Zn + Fe^(2+) is – 0.35 V. The given cell reaction is :

A quantity of 25.0 mL of solution containing both Fe^(2+) and Fe^(3+) ions is titrated with 25.0 mL of 0.0200 M KMnO_(4) (in dilute H_(2)SO_(4) ). As a result, all of the Fe^(2+) ions are oxidised to Fe^(3+) ions. Next 25 mL of the original solution is treated with Zn metal finally, the solution requires 40.0 mL of the same KMnO_(4) solution for oxidation to Fe^(3+) . MnO_(4)^(-)+5Fe^(2+)+8H^(+)toMn^(2+)+5Fe^(3+)+4H_(2)O Zinc aded in the second titration wil

Calculate the euilibrium constant for the reaction, 2Fe^(3+) + 3I^(-) hArr 2Fe^(2+) + I_(3)^(-) . The standard reduction potential in acidic conditions are 0.77 V and 0.54 V respectivelu for Fe^(3+)//Fe^(2+) and I_(3)^(-)//I^(-) couples.

Standard electrode potentials are Fe^(2+)//Fe, E^(@) = -0.44 V Fe^(3+)//Fe^(2+), E^(@) = +0.77 V If Fe^(3+), Fe^(2+) , and Fe block are kept together, then

If E_(Fe^(3+)//Fe)^(@) and E_(Fe^(2+)//Fe)^(@) are -0.36 V and 0.439 V respectively, then value of E_(Fe^(3+)//Fe^(2+))^(@) is

If E^(o)""_(Fe^(+2)//Fe) is x_(1),E^(o)""_(Fe ^(+3)//Fe) is x_(2), then E^(o) ""_(Fe^(+3)//Fe^(2+)) will be :