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Zn||ZnSO(4) (0.01M)||CuSO(4)(1.0M)Cu the...

`Zn||ZnSO_(4) (0.01M)||CuSO_(4)(1.0M)Cu` the emf of this Daniel cell is `E_(1)`. When the concentration `ZnSO_(4)` is changed to 1.0 M and that of `CuSO_(4)` changed to 0.01 M, the emf change to `E_(2)`. From the followings ,which one is the realtionship between `E_(1)` and `E_(2)`? ( Given , `(RT)/(F)=0.059`)

A

`E_(1) gt E_(2)`

B

`E_(1) lt E_(2)`

C

`E_(1) = E_(2)`

D

`E_(2) = 0 ne E_(1)`

Text Solution

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The correct Answer is:
A
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