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a. Would you expect the hydrides of N,O ...

a. Would you expect the hydrides of `N,O` and `F` to have lower boiling points than the hydrides of their subsequent group members? Give reason.
b. Can phosphorous with outer electronic configuration `3s^(2)3p^(3)` form `PH_(5)`?
c. How many hydrogen-bonded water molecules(s) are associated with `CuSO_(4).5H_(2)O`?

Text Solution

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On the basis of molecular masses of `NH_2, H_2O and HF`, their boiling points are expected to be lower than those of the next group member hydrides. However, due to higher electronegativity of N, O and F, the magnitude of hydrogen bonding in their hydrides will be quite appreciable. Hence, the boiling points of `NH_3, H_2O and HF` will be higher than the hydrides of their next group member.
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a. Would you except the hydrides of N,O and F to have lower boiling points than the hydrides of their subsequent group members? Give reason. b. Can phosphorous with outer electronic configuration 3s^(2)3p^(3) form PH_(5) ? c. How many hydrogen-bonded water molecules(s) are associated with CuSO_(4).5H_(2)O ?

How many hydrogen-bonded water molecule(s) are associated in CuSO_(4).5H_(2)O ?

How many hydrogen-bonded water molecule(s) are associated in CuSO_(4).5H_(2)O ?

How many hydrogen-bonded water molecule(s) are associated in CuSO_(4).5H_(2)O ?

Can phosphorus with outer electronic configureation 3s^2 3p^3 " form "PH_5 ?

Assertion : Hydrides of N, O and F have lower boiling points than the hydrides of their subsequent group members. Reason : Boiling point depends upon the molecular mass only.

How many sp^(3) hybridised atoms are there in one molecule of CuSO_(4).5H_(2)O ?

Assertion : CuSO_(4).5H_(2)O has one hydrogen-bonded molecule of water. Reason : The four molecules of water are coordinated in CuSO_(4).5H_(2)O .

The number of water molecule(s) derectly bonded to the metal centre in CuSO_4.5H_2O is

The electronic configuration of given speices (X) is 1s^(2), 2s^(2)2p^(6), 3s^(2)3p^(6)3d^(5), 4s^(1) . This can be its