Home
Class 12
CHEMISTRY
Why is K(a(2)) ltlt K(a(1)) for H(2) ...

Why is `K_(a_(2)) ltlt K_(a_(1))` for `H_(2) SO_(4)` in water ?

Text Solution

Verified by Experts

`H_(2) SO_(4)` is strong acid as its first ionization to `H_(3) O^(+)` and `H SO_(4)^(-)` is targe and further ionization is small.
Promotional Banner

Similar Questions

Explore conceptually related problems

For a 0.072 M NaSO_(4) solution,select the correct option(s): (K_(a_(1)) and K_(a_(2)) of H_(2)SO_(4)=oo & 1.2xx10^(-2))

If K_(a_(1))gtK_(a_(2)) of H_(2)SO_(4) are 10^(-2) and 10^(-6) respectively then:

The concentration of CO_(2) in atmosphere is 88ppm. If all of the CO_(2) present in 10^(5)mL of air is dissolved in 1dm^(3) water, then approximate pOH of solution at 27^(@)C will be (K_(a_(1)) = 10^(-7), K_(a_(2)) = 10^(-11) for H_(2)CO_(3)]

If osmotic presssure of 1M aqueous solution of H_(2)SO_(4) at 500 K is 90.2 atm. Calculate K_(a2) of H_(2)SO_(4) . Give your answer after multiplying 1000 with K_(a_(2)) . (Assumme ideal solution) [Given : K_(a_(1)) of H_(2)SO_(4)=oo ,R=0.082 L atm // mol-K]

Calculate the percent degree of hydrolysis of 0.005 M K_(2)CrO_(4).K_(a_(2))=5xx10^(-7) for H_(2)CrO_(4) .(it is essentially strong for first ionization)

Calculate solubility of MnS in a buffer solution of given pH.K_(sp) of MnS and K_(a_(1))&K_(a_(2)) for H_(2)S are given .

A reactant (A) forms two products A overset (k_(1))rarr B , Activation energy E_(a1) A overset (k_(2))rarr C , Activation energy E_(a2) If E_(a_(2)) = 2E_(a_(1)) then k_(1) and k_(2) are related as

A reactant (A) forms two products A overset (k_(1))rarr B , Activation energy E_(a1) A overset (k_(2))rarr C , Activation energy E_(a2) If E_(a_(2)) = 2E_(a_(1)) then k_(1) and k_(2) are related as

In a solution containing 0.1M HCl & 0.1M H_(3)PO_(4) (having dissociation constants K_(a_(1)),K_(a_(2)),K_(a_(3))) assuming alphaltlt1 for H_(3)PO_(4) ,

Acid rain takes place dur to combination of acidic oxides with water and it is an environmental concern all over the world. Assuming rain water is uncontaminated with HNO_(3) or H_(2)SO_(4) and is in equilibrium with 1.25 xx 10^(-4) atm CO_(2) . The Henry's law constant (K_(H)) is 1.25 xx 10^(6) "torr". K_(a_(1)) of H_(2)CO_(3) = 4.3 xx 10^(-7) What is the pH of neutral rain water ?