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White phosphorus occurs as discrete P4...

White phosphorus occurs as discrete `P_4` units , where P atom lie at the corners of a regular tetrahedron . The PPP bond angle is

A

`90^(@) `

B

`109^(@)28'`

C

`60^@`

D

`120^(@)`

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The correct Answer is:
To determine the bond angle in white phosphorus (P4), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Structure of White Phosphorus**: - White phosphorus consists of discrete P4 units. - In this structure, the phosphorus atoms are arranged at the corners of a regular tetrahedron. 2. **Visualizing the Tetrahedral Geometry**: - A tetrahedron has four vertices, and in the case of P4, each vertex represents a phosphorus atom. - The arrangement is three-dimensional, with each phosphorus atom bonded to the other three. 3. **Identifying the Bond Angles**: - In a regular tetrahedron, the bond angles between any two bonds originating from a single atom (in this case, phosphorus) are equal. - The bond angle we are interested in is the angle formed between two P-P bonds at a single phosphorus atom. 4. **Calculating the Bond Angle**: - The bond angle in a regular tetrahedron is known to be approximately 109.5 degrees. - However, in the context of the question, we are specifically looking for the angle between the P-P bonds, which is often referred to as the PPP bond angle. 5. **Conclusion**: - The PPP bond angle in white phosphorus (P4) is approximately 60 degrees due to the specific arrangement and the strain in the bonds. ### Final Answer: The PPP bond angle in white phosphorus is **60 degrees**. ---
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