When `F_(2)` gas reacts with `H_(2)O` it forms

Options

A. `O_(2)` gas
B. `O_(2) F_(2)`gas
C. HOF
D. Both (2) & (3)

Answer

To solve the question of what products are formed when \( F_2 \) gas reacts with \( H_2O \), we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are:
- Fluorine gas (\( F_2 \))
- Water (\( H_2O \))

### Step 2: Identify the Reaction
Fluorine is a highly reactive halogen and reacts vigorously with water. The general reaction can be represented as:
\[ F_2 + H_2O \rightarrow ? \]

### Step 3: Determine the Products
When \( F_2 \) reacts with \( H_2O \), it produces:
- Hydrogen fluoride (\( HF \))
- Oxygen gas (\( O_2 \))

The balanced chemical equation for this reaction is:
\[ 2F_2 + 2H_2O \rightarrow 4HF + O_2 \]

### Step 4: Analyze the Products
From the balanced equation, we can see that the products of the reaction are:
- Hydrogen fluoride (\( HF \))
- Oxygen gas (\( O_2 \))

### Step 5: Conclusion
Thus, when \( F_2 \) gas reacts with \( H_2O \), it forms both \( HF \) and \( O_2 \). The correct answer to the question is that it forms \( HF \) and \( O_2 \).

### Final Answer
When \( F_2 \) gas reacts with \( H_2O \), it forms \( HF \) and \( O_2 \).

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