`F_(2)` combines with `O_(2)` to form `O_(2) F_(2)` which are

Options

A. diOxygen difluorides
B. Oxides of fluorine
C. Anhydride of HOF
D. Both (2) & (3)

Answer

To solve the question, we need to analyze the reaction between \( F_2 \) (fluorine gas) and \( O_2 \) (oxygen gas) to form \( O_2F_2 \) (dioxygen difluoride). We will also evaluate the provided options to determine the correct answer.

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The reactants in the reaction are \( F_2 \) (fluorine gas) and \( O_2 \) (oxygen gas).

2. **Determine the Product:**
- When \( F_2 \) combines with \( O_2 \), it forms \( O_2F_2 \).

3. **Naming the Product:**
- The chemical formula \( O_2F_2 \) can be named by identifying the elements present:
- There are two oxygen (O) atoms and two fluorine (F) atoms.
- The systematic name for \( O_2F_2 \) is dioxygen difluoride.

4. **Analyze the Options:**
- **Option 1:** Dioxygen Difluoride - This is correct as we have identified \( O_2F_2 \) as dioxygen difluoride.
- **Option 2:** Oxide of Fluorine - This is also correct because \( O_2F_2 \) can be considered a compound of oxygen and fluorine.
- **Option 3:** Anhydride of HOF - This is not correct. HOF (hypofluorous acid) does not have a direct relationship with \( O_2F_2 \).
- **Option 4:** Both second and third - Since option 3 is incorrect, this option cannot be correct.

5. **Conclusion:**
- The correct answer is **Option 1: Dioxygen Difluoride**. However, since option 2 (oxide of fluorine) is also correct, the best choice based on the options provided would be **Option 4: both second and third** if we consider the context of the question.

### Final Answer:
- The correct answer is **Option 1: Dioxygen Difluoride**.