The order of acidity of oxides of chlorine .
`{:(Cl_(2) O ,, Cl_(2) O_(3) ,, Cl_(2) O_(5) ,, Cl_(2)O_(7)), (I ,, II ,, III ,, IV):}` is

Options

A. `I lt II lt III lt IV `
B. `I gt II gt III gt IV`
C. `I gt III gt II gt IV`
D. `IV gt I gt II gt III`

Answer

To determine the order of acidity of the oxides of chlorine (Cl₂O, Cl₂O₃, Cl₂O₅, Cl₂O₇), we will follow these steps:

### Step 1: Identify the Oxidation States
We need to calculate the oxidation state of chlorine in each oxide.

1. **For Cl₂O:**
- Let the oxidation state of Cl be \( x \).
- The oxidation state of O is \(-2\).
- The equation is:
\[ 2x + (-2) = 0 \implies 2x = 2 \implies x = +1 \]

2. **For Cl₂O₃:**
- Let the oxidation state of Cl be \( x \).
- The equation is:
\[ 2x + 3(-2) = 0 \implies 2x - 6 = 0 \implies 2x = 6 \implies x = +3 \]

3. **For Cl₂O₅:**
- Let the oxidation state of Cl be \( x \).
- The equation is:
\[ 2x + 5(-2) = 0 \implies 2x - 10 = 0 \implies 2x = 10 \implies x = +5 \]

4. **For Cl₂O₇:**
- Let the oxidation state of Cl be \( x \).
- The equation is:
\[ 2x + 7(-2) = 0 \implies 2x - 14 = 0 \implies 2x = 14 \implies x = +7 \]

### Step 2: Determine Acidity Based on Oxidation State
The acidity of oxides generally increases with the oxidation state of the central atom. Therefore, we can arrange the oxides based on the oxidation states we calculated:

- Cl₂O: +1 (least acidic)
- Cl₂O₃: +3
- Cl₂O₅: +5
- Cl₂O₇: +7 (most acidic)

### Step 3: Order of Acidity
Based on the oxidation states, the order of acidity from least to most acidic is:
\[ \text{Cl}_2\text{O} < \text{Cl}_2\text{O}_3 < \text{Cl}_2\text{O}_5 < \text{Cl}_2\text{O}_7 \]
This translates to:
\[ 1 < 2 < 3 < 4 \]
Thus, the order of acidity is:
\[ \text{Cl}_2\text{O}_7 > \text{Cl}_2\text{O}_5 > \text{Cl}_2\text{O}_3 > \text{Cl}_2\text{O} \]

### Final Answer
The order of acidity of the oxides of chlorine is:
\[ \text{Cl}_2\text{O}_7 > \text{Cl}_2\text{O}_5 > \text{Cl}_2\text{O}_3 > \text{Cl}_2\text{O} \]
Thus, the correct option is:
\[ 4 > 3 > 2 > 1 \]