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Which of the following statement is corr...

Which of the following statement is correct ?

A

Boron and aluminium halides behave as Lewis acids

B

Al forms `[Al F_(6)]^(3-)` ion but B does not form `[BF_(6)]^(3-)` ion

C

The `p pi - p pi` back bonding occurs in the halides of boron and not in those of aluminium

D

All of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the statements regarding boron and aluminum is correct, we will analyze each statement step by step. ### Step 1: Analyze the Lewis Acid Behavior of Boron and Aluminum - **Boron (BH3)**: Boron has only 6 electrons in its valence shell (2 from 2s and 4 from 2p). It is electron-deficient and can accept a pair of electrons to complete its octet, thus behaving as a Lewis acid. - **Aluminum (AlH3)**: Similarly, aluminum also has only 6 valence electrons (3 from 3s and 3 from 3p). It can also accept a pair of electrons to complete its octet, behaving as a Lewis acid as well. **Conclusion**: Both boron and aluminum behave as Lewis acids. ### Step 2: Analyze the Formation of AlF6^3- and BF6^3- - **Aluminum**: Aluminum can expand its octet due to the presence of vacant d-orbitals in the third period. Therefore, it can form AlF6^3-. - **Boron**: Boron does not have vacant d-orbitals (it only has 1s, 2s, and 2p orbitals). Thus, it cannot expand its octet and cannot form BF6^3-. **Conclusion**: The statement that aluminum forms AlF6^3- but boron does not form BF6^3- is correct. ### Step 3: Analyze p-pi p-pi Back Bonding - **Boron Halides**: Boron has a smaller atomic size and can effectively engage in p-pi p-pi back bonding due to its ability to overlap with p orbitals of halogens. - **Aluminum Halides**: Aluminum, being larger, has less effective p-pi p-pi back bonding due to the larger size of the aluminum atom compared to boron. **Conclusion**: The statement that p-pi p-pi back bonding occurs in the halides of boron but not in those of aluminum is also correct. ### Final Conclusion After analyzing all the statements: 1. Both boron and aluminum behave as Lewis acids. 2. Aluminum can form AlF6^3- while boron cannot form BF6^3-. 3. p-pi p-pi back bonding occurs in boron halides but not in aluminum halides. Thus, the correct answer is that all of the statements provided are correct.
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