When `SiCl_(4)` is allowed to undergo hydrolysis it gives

Options

A. `SiO_(2)` - Silicic acid
B. `Si(OH)_(4)` - Silicic acid
C. `Si(OH) Cl_(3)` - Silicic acid
D. `SiCl_4` do not undergo hydrolysis

Answer

To solve the question regarding the hydrolysis of silicon tetrachloride (SiCl₄), we can follow these steps:

### Step 1: Understand the Hydrolysis Reaction
Silicon tetrachloride (SiCl₄) is a chemical compound that can react with water (H₂O) in a hydrolysis reaction. Hydrolysis typically involves the reaction of a substance with water to form new products.

### Step 2: Write the Hydrolysis Reaction
When SiCl₄ undergoes hydrolysis, the reaction can be represented as follows:
\[ \text{SiCl}_4 + 2 \text{H}_2\text{O} \rightarrow \text{Si(OH)}_4 + 4 \text{HCl} \]

### Step 3: Identify the Products
From the reaction, we can see that the products formed are:
1. Silicic acid (Si(OH)₄)
2. Hydrochloric acid (HCl)

### Step 4: Analyze the Options
Now, let's analyze the options given in the question:
- Option 1: SiO₂ (Silicon dioxide) - This is incorrect as it is not formed directly in this reaction.
- Option 2: Si(OH)₄ (Silicic acid) - This is correct as it is formed during hydrolysis.
- Option 3: Si(OH)Cl₃ - This is incorrect as it does not represent the product of the hydrolysis reaction.
- Option 4: SiCl₄ does not undergo hydrolysis - This is incorrect as SiCl₄ does indeed undergo hydrolysis.

### Step 5: Conclusion
Therefore, the correct answer to the question is:
**Si(OH)₄ (Silicic acid)**.