`CH_3 Cl + Si overset(Cu "Powder")underset(570 )(to) X overset(2 H_2 O)(to) Y`
Y & X respectively are

Options

A. `(CH_(3))_(2) SiCl_(2) , (CH_(3))_(2) Si(OH)_(2)`
B. `(CH_(3))_(2) Si(OH)_(2) , (CH_(3))_(2) SiCl_(2)`
C. `SiCl_4 , Si(OH)_(4)`
D. `Si(OH)_(4) , SiCl_4`

Answer

To solve the problem step by step, we will analyze the given reaction and identify the products formed.

### Step 1: Identify the Reactants
The given reactants are:
- Methyl chloride (CH₃Cl)
- Silicon (Si)
- Copper powder (Cu) as a catalyst
- The reaction occurs at a temperature of 570 K.

### Step 2: Determine the Reaction
When methyl chloride (CH₃Cl) reacts with silicon (Si) in the presence of copper powder at 570 K, a silicon compound is formed. The expected product from this reaction is dimethylchlorosilane, which can be represented as:
\[ \text{Si(CH}_3\text{)}_2\text{Cl}_2 \]
This can also be written as:
\[ \text{CH}_3\text{O}_2\text{SiCl}_2 \]
Thus, we can denote this product as X:
\[ X = \text{Si(CH}_3\text{)}_2\text{Cl}_2 \]

### Step 3: Hydrolysis of Product X
Next, we treat product X with water (H₂O). The hydrolysis of dimethylchlorosilane (X) leads to the formation of a silanol compound. The reaction can be represented as:
\[ \text{Si(CH}_3\text{)}_2\text{Cl}_2 + 2 \text{H}_2\text{O} \rightarrow \text{Si(CH}_3\text{)}_2\text{(OH)}_2 + 2 \text{HCl} \]
This product can be denoted as Y:
\[ Y = \text{Si(CH}_3\text{)}_2\text{(OH)}_2 \]

### Step 4: Final Products
From the above reactions, we conclude that:
- Product X is dimethylchlorosilane: \[ \text{Si(CH}_3\text{)}_2\text{Cl}_2 \]
- Product Y is dimethylsilanediol: \[ \text{Si(CH}_3\text{)}_2\text{(OH)}_2 \]

### Conclusion
Thus, the final answer is:
- X = \[ \text{Si(CH}_3\text{)}_2\text{Cl}_2 \]
- Y = \[ \text{Si(CH}_3\text{)}_2\text{(OH)}_2 \]