Phosphine on reaction with hydrobromic acid gives

Options

A. `PBr_(3)`
B. `P_(2) H_(4) Br_(2)`
C. `PBr_(5)`
D. `PH_(4) Br`

Answer

To solve the question regarding the reaction of phosphine with hydrobromic acid, let's break it down step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are phosphine (PH₃) and hydrobromic acid (HBr).

2. **Understand the Nature of the Reactants**:
- Phosphine (PH₃) is a neutral molecule, while hydrobromic acid (HBr) is a strong acid that can donate a proton (H⁺).

3. **Reaction Mechanism**:
- When phosphine reacts with hydrobromic acid, the HBr donates a proton (H⁺) to the phosphine molecule. This results in the formation of a positively charged phosphonium ion (PH₄⁺).

4. **Formation of the Product**:
- The phosphonium ion (PH₄⁺) then combines with the bromide ion (Br⁻) from HBr to form phosphonium bromide (PH₄Br).

5. **Write the Balanced Chemical Equation**:
- The balanced equation for the reaction can be written as:
\[ PH₃ + HBr \rightarrow PH₄Br \]

6. **Identify the Correct Product**:
- From the options provided:
- PBr₃ (wrong)
- P₂H₄Br₂ (wrong)
- PBr₅ (wrong)
- PH₄Br (correct)
- Therefore, the product formed from the reaction is phosphonium bromide (PH₄Br).

### Final Answer:
The reaction of phosphine with hydrobromic acid gives phosphonium bromide (PH₄Br).

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