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Calomel (Hg(2)Cl(2)) on reaction with am...

Calomel `(Hg_(2)Cl_(2))` on reaction with ammonium hydroxide gives

A

`Hg_2 O`

B

`HgO`

C

`HgN H_(2) Cl`

D

`NH_(2) Hg_2 Cl`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the reaction of calomel (Hg₂Cl₂) with ammonium hydroxide (NH₄OH), we will follow these steps: ### Step 1: Identify the Reactants The reactants in this reaction are calomel (Hg₂Cl₂) and ammonium hydroxide (NH₄OH). ### Step 2: Write the Reaction When calomel reacts with ammonium hydroxide, the reaction can be represented as: \[ \text{Hg}_2\text{Cl}_2 + 2 \text{NH}_4\text{OH} \rightarrow \text{Hg} + \text{HgNH}_2\text{Cl} + 2 \text{H}_2\text{O} + 2 \text{NH}_4\text{Cl} \] ### Step 3: Identify the Products The products of the reaction include: 1. Mercury (Hg) 2. Mercuric amino chloride (HgNH₂Cl) 3. Water (H₂O) 4. Ammonium chloride (NH₄Cl) ### Step 4: Analyze the Result The black mass formed during the reaction is a mixture of mercury and mercuric amino chloride, which indicates that the reaction has produced these substances. ### Step 5: Conclusion From the analysis of the products, we can conclude that the main product of the reaction between calomel and ammonium hydroxide is mercuric amino chloride (HgNH₂Cl). ### Final Answer The reaction of calomel (Hg₂Cl₂) with ammonium hydroxide gives mercuric amino chloride (HgNH₂Cl). ---
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