What is the product formed when `NH_(3)` reacts with excess of `Cl_(2)` ?

Options

A. `NH_(4) Cl` & HCl
B. `NH_(4) Cl ` & `N_(2)`
C. `NCl_3` & HCl
D. `NH_4 Cl ` & `NCl_3`

Answer

To determine the products formed when ammonia (NH₃) reacts with excess chlorine (Cl₂), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Ammonia (NH₃)
- Chlorine (Cl₂)

### Step 2: Understand the Reaction Conditions
Since the problem states that there is an excess of chlorine, this will influence the products formed. Excess chlorine means that there will be enough chlorine to react with all available ammonia and possibly more.

### Step 3: Write the Balanced Chemical Equation
When ammonia reacts with chlorine, the reaction can be represented as follows:
\[ \text{Cl}_2 + \text{NH}_3 \rightarrow \text{NCl}_3 + \text{HCl} \]

### Step 4: Identify the Products
From the balanced equation, we can see that the products formed are:
- Nitrogen trichloride (NCl₃)
- Hydrochloric acid (HCl)

### Step 5: Conclusion
Thus, when ammonia reacts with excess chlorine, the products formed are nitrogen trichloride (NCl₃) and hydrochloric acid (HCl).

### Final Answer
The products formed when NH₃ reacts with excess Cl₂ are NCl₃ and HCl.

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