In xenon fluorides most reactive in `XeF_(6) , XeF_(4)` and `XeF_(2)` is

Options

A. `XeF_(6)`
B. `XeF_(2)`
C. `XeF_(4)`
D. All are equally reactive

Answer

To determine which xenon fluoride is the most reactive among XeF6, XeF4, and XeF2, we can follow these steps:

### Step 1: Identify the oxidation states of xenon in each fluoride.
- **For XeF6**:
- Xenon (Xe) has 8 valence electrons. Each fluorine (F) atom is more electronegative and will take one electron from xenon.
- In XeF6, xenon forms 6 bonds with fluorine. Therefore, the oxidation state of xenon is +6.

- **For XeF4**:
- In XeF4, xenon forms 4 bonds with fluorine. This leaves 4 valence electrons (8 - 4 = 4). Thus, the oxidation state of xenon is +4.

- **For XeF2**:
- In XeF2, xenon forms 2 bonds with fluorine. This leaves 6 valence electrons (8 - 2 = 6). Thus, the oxidation state of xenon is +2.

### Step 2: Compare the oxidation states.
- XeF6: +6
- XeF4: +4
- XeF2: +2

### Step 3: Determine the reactivity based on oxidation states.
- The reactivity of these xenon fluorides is directly related to the oxidation state of xenon. Higher oxidation states indicate a greater tendency to react because the central atom (xenon) has a stronger positive charge, which can attract more electrons from other species.

### Conclusion:
Since XeF6 has the highest oxidation state of +6, it is the most reactive among XeF6, XeF4, and XeF2.

### Final Answer:
The most reactive xenon fluoride is **XeF6**.

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