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Reaction of Cl(2) with hot and conc. NaO...

Reaction of `Cl_(2)` with hot and conc. `NaOH` produces

A

NaClO

B

`NaClO_(3)`

C

`NaClO_(4)`

D

`NaClO_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the reaction of \( \text{Cl}_2 \) with hot and concentrated \( \text{NaOH} \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactants in this reaction are chlorine gas (\( \text{Cl}_2 \)) and hot, concentrated sodium hydroxide (\( \text{NaOH} \)). 2. **Understand the Reaction Conditions**: The reaction is taking place under hot and concentrated conditions, which indicates that the chlorine will react vigorously with sodium hydroxide. 3. **Write the Reaction**: The general reaction can be written as: \[ \text{Cl}_2 + \text{NaOH} \rightarrow \text{Products} \] 4. **Determine the Products**: When \( \text{Cl}_2 \) reacts with hot and concentrated \( \text{NaOH} \), it forms sodium chloride (\( \text{NaCl} \)) and sodium chlorate (\( \text{NaClO}_3 \)). The balanced reaction is: \[ 3 \text{Cl}_2 + 6 \text{NaOH} \rightarrow 5 \text{NaCl} + \text{NaClO}_3 + 3 \text{H}_2\text{O} \] 5. **Identify the Correct Option**: From the products formed, we see that \( \text{NaClO}_3 \) (sodium chlorate) is one of the products along with sodium chloride (\( \text{NaCl} \)). 6. **Conclusion**: Therefore, the correct answer to the question is that the reaction of \( \text{Cl}_2 \) with hot and concentrated \( \text{NaOH} \) produces sodium chlorate (\( \text{NaClO}_3 \)). ### Final Answer: The reaction of \( \text{Cl}_2 \) with hot and concentrated \( \text{NaOH} \) produces \( \text{NaCl} \) and \( \text{NaClO}_3 \). ---
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