Oxalic acid on treatment with conc. `H_(2) SO_(4)` gives

Options

A. CO only
B. `CO_(2)` only
C. `CO_(2) + H_(2)O`
D. `CO + CO_(2) + H_(2)O`

Answer

To solve the question regarding the products formed when oxalic acid is treated with concentrated sulfuric acid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactant in this case is oxalic acid, which has the chemical formula \( \text{C}_2\text{H}_2\text{O}_4 \) or \( \text{(COOH)}_2 \).

2. **Understand the Role of Concentrated Sulfuric Acid**: Concentrated sulfuric acid (\( \text{H}_2\text{SO}_4 \)) acts as a dehydrating agent. This means it can remove water molecules from other substances.

3. **Write the Reaction**: When oxalic acid is heated with concentrated sulfuric acid, the dehydration reaction occurs. The reaction can be represented as:
\[ \text{C}_2\text{H}_2\text{O}_4 + \text{H}_2\text{SO}_4 \rightarrow \text{CO} + \text{CO}_2 + \text{H}_2\text{O} \]

4. **Identify the Products**: The products formed from the reaction are:
- Carbon monoxide (\( \text{CO} \))
- Carbon dioxide (\( \text{CO}_2 \))
- Water (\( \text{H}_2\text{O} \))

5. **Conclusion**: Therefore, the correct answer to the question is that oxalic acid on treatment with concentrated sulfuric acid gives \( \text{CO} + \text{CO}_2 + \text{H}_2\text{O} \).

### Final Answer:
The products formed when oxalic acid is treated with concentrated \( \text{H}_2\text{SO}_4 \) are \( \text{CO} + \text{CO}_2 + \text{H}_2\text{O} \).

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