Pb on reaction with conc. `HNO_3` gives

Options

A. `Pb(NO_(3))_(2) + NO_(2)`
B. `PbNO_(3) + N_(2)O`
C. `Pb(NO_(3))_(2) + N_(2) O_(3)`
D. `Pb(NO_(3))_(2) + N_(2)O`

Answer

To determine the products of the reaction between lead (Pb) and concentrated nitric acid (HNO₃), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are lead (Pb) and concentrated nitric acid (HNO₃).

2. **Understand the Nature of Concentrated HNO₃**:
Concentrated nitric acid is a strong oxidizing agent. This means it can oxidize metals and other substances during a chemical reaction.

3. **Determine the Oxidation Process**:
When lead reacts with concentrated nitric acid, it gets oxidized. Lead (Pb) is oxidized to lead ions (Pb²⁺).

4. **Identify the Products**:
The main products of this reaction are:
- Lead(II) nitrate (Pb(NO₃)₂)
- Nitrogen dioxide (NO₂) as a byproduct of the oxidation process.

5. **Write the Balanced Chemical Equation**:
The balanced chemical equation for the reaction can be written as:
\[ 3 \text{Pb} + 8 \text{HNO}_3 \rightarrow 3 \text{Pb(NO}_3\text{)}_2 + 2 \text{NO}_2 + 4 \text{H}_2\text{O} \]
This shows that three moles of lead react with eight moles of nitric acid to produce three moles of lead(II) nitrate, two moles of nitrogen dioxide, and four moles of water.

6. **Select the Correct Option**:
From the options given in the question, the correct answer is:
\[ \text{Pb(NO}_3\text{)}_2 + \text{NO}_2 \]
This corresponds to option A: Pb(NO₃)₂ + NO₂.

### Final Answer:
Lead (Pb) on reaction with concentrated HNO₃ gives lead(II) nitrate (Pb(NO₃)₂) and nitrogen dioxide (NO₂).

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