With F highest stable oxidation state of Mn is

Options

A. `+6`
B. `+4`
C. `+7`
D. `+3`

Answer

To determine the highest stable oxidation state of manganese (Mn) when it is combined with fluorine (F), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Oxidation States**:
- Manganese can exhibit multiple oxidation states, ranging from -3 to +7. The highest oxidation state of manganese is +7.

2. **Fluorine's Characteristics**:
- Fluorine is highly electronegative and typically forms only single bonds. Each fluorine atom can form one bond and has three lone pairs of electrons.

3. **Formation of MnF Compounds**:
- When manganese reacts with fluorine, it can form compounds like MnF4. The maximum number of fluorine atoms that can bond with manganese is limited due to the repulsion between the lone pairs of electrons on the fluorine atoms.

4. **Determining the Stable Compound**:
- In MnF4, manganese is bonded to four fluorine atoms. The oxidation state of manganese can be calculated using the formula:
\[ \text{Oxidation state of Mn} (X) + 4 \times (-1) = 0 \]
\[ X - 4 = 0 \implies X = +4 \]

5. **Conclusion**:
- The highest stable oxidation state of manganese with fluorine is +4. This is because the presence of four fluorine atoms leads to inter-electronic repulsions that prevent the formation of higher oxidation states like +6 or +7.

### Final Answer:
The highest stable oxidation state of manganese with fluorine is **+4**.

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