Which of the following shows maximum number of oxidation states :-

Options

A. Cr
B. Fe
C. Mn
D. V

Answer

To determine which element shows the maximum number of oxidation states among the given options (Chromium, Iron, Manganese, and Vanadium), we will analyze the electronic configurations and the maximum oxidation states of each element.

### Step-by-Step Solution:

1. **Identify the Elements and Their Electronic Configurations**:
- **Chromium (Cr)**:
- Electronic configuration: Argon (Ar) 3d⁵ 4s¹
- **Iron (Fe)**:
- Electronic configuration: Argon (Ar) 4s² 3d⁶
- **Manganese (Mn)**:
- Electronic configuration: Argon (Ar) 3d⁵ 4s²
- **Vanadium (V)**:
- Electronic configuration: Argon (Ar) 3d³ 4s²

2. **Determine the Maximum Oxidation States**:
- **Chromium (Cr)**:
- Maximum oxidation state = +6 (can lose 6 electrons)
- **Iron (Fe)**:
- Maximum oxidation state = +6 (can lose 6 electrons, but commonly +2 and +3)
- **Manganese (Mn)**:
- Maximum oxidation state = +7 (can lose all 7 electrons)
- **Vanadium (V)**:
- Maximum oxidation state = +5 (can lose 5 electrons)

3. **Compare the Maximum Oxidation States**:
- Chromium: +6
- Iron: +6
- Manganese: +7
- Vanadium: +5

4. **Conclusion**:
- Among the elements analyzed, Manganese (Mn) shows the maximum oxidation state of +7.

### Final Answer:
Manganese (Mn) shows the maximum number of oxidation states.

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