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A: I.E. of 5d elements > 4d elements in ...

A: I.E. of 5d elements > 4d elements in general.
R: It is due to lanthanoid contraction.

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1)

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)

C

If Assertion is true statement but Reason is false, then mark (3)

D

If both Assertion and Reason are false statements, then mark (4)

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the given assertion and reason, we will break down the concepts step by step. ### Step 1: Understand the Assertion The assertion states that the ionization energy (I.E.) of 5d elements is greater than that of 4d elements in general. **Explanation:** - Ionization energy is the energy required to remove an electron from an atom in its gaseous state. - The 5d block elements are transition metals that have their outermost electrons in the 5d subshell, while the 4d block elements have their outermost electrons in the 4d subshell. ### Step 2: Understand the Reason The reason provided is that this trend is due to lanthanoid contraction. **Explanation:** - Lanthanoid contraction refers to the phenomenon where the atomic and ionic sizes of the lanthanide series elements decrease with increasing atomic number due to the poor shielding effect of the f-orbitals. - This contraction affects the 5d elements because the increased nuclear charge (more protons) in these elements leads to a smaller atomic size compared to the 4d elements. ### Step 3: Analyze the Relationship Between Assertion and Reason Now, we need to see if the reason provided correctly explains the assertion. - Due to lanthanoid contraction, the atomic size of 5d elements is smaller than that of 4d elements. - A smaller atomic size means that the outer electrons are closer to the nucleus, which increases the effective nuclear charge experienced by these electrons. - As a result, the outer electrons in 5d elements are held more tightly by the nucleus, leading to higher ionization energy compared to 4d elements. ### Conclusion Both the assertion and reason are correct. The reason (lanthanoid contraction) accurately explains why the ionization energy of 5d elements is greater than that of 4d elements. ### Final Answer Both assertion and reason are true, and the reason is the correct explanation of the assertion. ---
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Assign reasons for the following : (i) Cu(I) ion is not known to exist in aqueous solutions. (ii) Transition metals are much harder than the alkali metals. (iii) From element to element, actinoid contraction is greater than the lanthanoid contraction.

Assertion : 4d and 5d series elements have nearly same atomic radius. Reason : Lanthanoid contraction.

D and f block elements

Assign reasons for the following : (i) The enthalpies of atomisation of transition elements are high. (ii) The transition metals and many of their compounds act as good catalyst. (iii) From element to element the actinoid contraction is greater than the lanthanoid contraction. (iv) The E^(@) value for the Mn^(3+)//Mn^(2+) couple is much more positive than that for Cr^(3+)//Cr^(2+) . (v) Scandium (Z = 21) does not exhibit variable oxidation states and yet it is regarded as transition element.

In case of d-block elements

D and F block elements

Actinoid contraction is greater from element to element than lanthanoid contraction Why?

The gradual decrease in size (actionoid contraction) is from element to element is greater among the actinoids than that among the lanthanoids (lanthanoid contraction).

Give an explanation for each of the following observations: (i) The gradual decrease in size (actinoid con-traction) from element to element is greater among the actinoids than that among the lanthanoids (lanthanoid contraction). (ii) The greater number of oxidation states are exhibited by the members in the middle of a transition series. (iii) With the same d-orbital (d^4) , Cr^(2+) ion is a reducing agent but Mn^(3+) ion is an oxidising agent.

Complete the following chemical equation: (i) MnO_(4)^(-)(aq)+s_(2)O_(3)^(2-)(aq)+H_(2)O(I) to (ii) MnO_(4)^(-) +NO_(2)^(-)+H^(+) to State reason for the following : (i) Cu(I) ion is not stable in an aqueous solution. (ii) Unlike Cr^(3+),Mn^(2+),Fe^(3+) and the subsequently other M^(2+) ions of the 3d series of elements, the 4d and the 5d series metals generally do not form stable cationic species.

AAKASH INSTITUTE ENGLISH- ALCOHOLS, PHENOLS AND ETHERS-Assignment Section -D (Assertion - reason type question)
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  4. A : When 3,3-dimethyl butan - 2 - ol is heated in presence of concentr...

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  5. A : In esterification reaction , HCOOH is the most reactive acid among...

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  6. A : Ethers can't be distilled upto dryness due to fear of explosion . ...

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  7. Phenol is less acidic than........... .

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  8. A : CH(3) - underset(O)underset(||)(C)-COOH gives haloform reaction ...

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  9. A : Diphenyl ether is prepared by Williamson synthesis . R : This...

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  10. A : Grignard's reagent is prepared in the presence of ether . R :...

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  11. A : CH(3) - underset(CH(3))underset(|)overset(CH(3))overset(|)(C)-CH=...

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  12. A : Two moles of Grignard reagent is consumed in the formation of ter...

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  13. A : bond angle in ether is slightly greater than normal tetrahedral an...

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  14. A : CH(3)-underset(CH(3))underset(|)overset(CH(3))overset(|)(C)-O-CH...

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  15. A : Ortho - cresol is weaker acidic than meta-cresol . R : It is d...

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  16. A : Among all ortho halophenol , fluorophenol is least acidic . R ...

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  17. A : In esterification reaction alcohol act as nucleophile . R : ...

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  18. A : Phenol is manufactured by Dow 's pocess. R : It involves the ...

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  19. A : Primary alcohol is prepared by the reaction of primary amine with ...

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  20. A : The reactivity order of alcohols is 1^(@) gt 2^(@) gt 3^(@) for ...

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