Which of the following will give maximum NO. of ions in water?

Options

A. `KCI.MgCl_(2).6H_(2)O`
B. `K_(4)[Fe(CN)_(8)]`
C. `K_(3)[Fe(CN)_(6)]`
D. `[Ag(CN)_(2)]^(-)`

Answer

To determine which of the given compounds will produce the maximum number of ions when dissolved in water, we need to analyze each option step by step.

### Step 1: Analyze each compound

1. **KCl·Mg(CN)₂·6H₂O**
- This is a double salt. When it dissolves in water, it dissociates into:
- K⁺ ions (1 from KCl)
- Cl⁻ ions (1 from KCl)
- Mg²⁺ ions (1 from Mg(CN)₂)
- 2 CN⁻ ions (from Mg(CN)₂)
- Total ions produced: 1 K⁺ + 1 Cl⁻ + 1 Mg²⁺ + 2 CN⁻ = 5 ions.

2. **K₄[Fe(CN)₆]**
- This is a complex ion. When it dissolves, it dissociates into:
- 4 K⁺ ions
- 1 [Fe(CN)₆]⁴⁻ ion
- Total ions produced: 4 K⁺ + 1 [Fe(CN)₆]⁴⁻ = 5 ions.

3. **K₃[Fe(CN)₆]**
- This is also a complex ion. When it dissolves, it dissociates into:
- 3 K⁺ ions
- 1 [Fe(CN)₆]³⁻ ion
- Total ions produced: 3 K⁺ + 1 [Fe(CN)₆]³⁻ = 4 ions.

4. **AgCN**
- This is a simple ionic compound. When it dissolves, it dissociates into:
- 1 Ag⁺ ion
- 1 CN⁻ ion
- Total ions produced: 1 Ag⁺ + 1 CN⁻ = 2 ions.

### Step 2: Compare the total number of ions produced

- **KCl·Mg(CN)₂·6H₂O**: 5 ions
- **K₄[Fe(CN)₆]**: 5 ions
- **K₃[Fe(CN)₆]**: 4 ions
- **AgCN**: 2 ions

### Step 3: Conclusion

The compounds KCl·Mg(CN)₂·6H₂O and K₄[Fe(CN)₆] both produce the maximum number of ions, which is 5 ions.

### Final Answer:
The compounds that give the maximum number of ions in water are **KCl·Mg(CN)₂·6H₂O** and **K₄[Fe(CN)₆]**.

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