The compound `PtCI_(2) 2NH_(3)` does not react with `AgNO_(3)` This compound can be represented as

Options

A. `[PtCI_(2)](NH_(3))_(2)`
B. `[PtCI_(2)(NH_(3))_(2)]`
C. `[Pt(NH_(3))_(2)]CI_(2)`
D. `[Pt(NH_(3))_(2)CI]CI_(2)`

Answer

To solve the problem regarding the compound \( PtCl_2 \cdot 2NH_3 \) and its reactivity with \( AgNO_3 \), we need to analyze the structure and bonding of the compound. Here’s a step-by-step breakdown of the solution:

### Step 1: Understanding the Compound
The compound in question is \( PtCl_2 \cdot 2NH_3 \). It consists of platinum (Pt), chloride ions (Cl), and ammonia (NH3) as ligands.

### Step 2: Analyzing Reactivity with \( AgNO_3 \)
The question states that this compound does not react with \( AgNO_3 \). Typically, \( AgNO_3 \) reacts with free chloride ions to form a precipitate of silver chloride (\( AgCl \)). If there are no free chloride ions available, the compound will not react with \( AgNO_3 \).

### Step 3: Determining the Structure
Since the compound does not react with \( AgNO_3 \), we can conclude that all the chloride ions must be coordinated to the platinum ion as ligands rather than being free ions. This means that the structure of the compound must be such that the chloride ions are part of the coordination sphere of the platinum.

### Step 4: Writing the Correct Formula
Given that there are two chloride ions and two ammonia molecules coordinated to platinum, the correct representation of the compound can be written as:
\[ [Pt(NH_3)_2Cl_2] \]
This indicates that platinum is surrounded by two ammonia ligands and two chloride ligands.

### Conclusion
Thus, the compound \( PtCl_2 \cdot 2NH_3 \) can be represented as:
\[ [Pt(NH_3)_2Cl_2] \]