Coordination isomerism exhibited by

Options

A. `[Cr(en)_(2)CI^(2)]NO_(2)`
B. `[Cr(NH)_(3))_(5)Br]SO_(4)`
C. `[Pt(NH_(3))_(4)][CUCI_(4)]`
D. `[Co(NH_(3))_(5)CI]CI_(2)`

Answer

To determine which of the given complexes exhibit coordination isomerism, we need to analyze each option based on the definition of coordination isomers.

### Step-by-Step Solution:

1. **Understand Coordination Isomerism**:
- Coordination isomerism occurs when there are two different coordination spheres in a complex. This means that the ligands can be distributed differently between the cationic and anionic parts of the complex.

2. **Analyze Each Complex**:
- **Option A: Cr(En)2(Cl)2(NO2)**: This complex has a chromium center with two ethylenediamine (En) ligands, two chloride (Cl) ligands, and one nitrite (NO2) ligand. It does not have two distinct coordination spheres, so it does not exhibit coordination isomerism.

- **Option B: Cr(NH3)2(O5)BrSO4**: This complex contains chromium with two amine ligands, one bromide, and one sulfate. Similar to option A, it does not have two distinct coordination spheres, so it does not exhibit coordination isomerism.

- **Option C: Pt(NH3)4CuClO4**: This complex has platinum with four ammonia ligands and a copper ion with a chloride and a sulfate ion. The presence of two different metal centers (Pt and Cu) suggests that there could be different arrangements of ligands between the cationic and anionic parts, indicating the possibility of coordination isomerism.

- **Option D: Cu(NH3)5Cl2**: This complex has copper with five ammonia ligands and two chloride ions. Since there is only one metal center and no distinct cationic and anionic spheres, it does not exhibit coordination isomerism.

3. **Identify the Correct Option**:
- Based on the analysis, **Option C: Pt(NH3)4CuClO4** is the only complex that can exhibit coordination isomerism due to the presence of different coordination spheres.

### Final Answer:
Coordination isomerism is exhibited by **Option C: Pt(NH3)4CuClO4**.