IUPAC name of `H_(2)[PtCl_(6)]` is

Options

A. ) Dihydrogen hexachloridoplatinum (IV)
B. Hexachloridoplatinic (IV) acid
C. Dihydrogen hexachloridoplatinic (IV) acid
D. Hexachloridoplatinum (IV) acid

Answer

To determine the IUPAC name of the coordination compound \( H_2[PtCl_6] \), we can follow these steps:

### Step 1: Identify the components of the complex
The complex consists of a cation \( H_2^+ \) and an anionic coordination complex \( [PtCl_6]^{2-} \).

### Step 2: Determine the oxidation state of platinum
Let the oxidation state of platinum (Pt) be \( x \). The chlorido ligands (Cl) are negatively charged, contributing a total of \( -6 \) (since there are 6 Cl ligands, each with a charge of -1). The overall charge of the complex is -2. We can set up the equation:

\[ x + (-6) = -2 \]

Solving for \( x \):

\[ x - 6 = -2 \\ x = +4 \]

Thus, platinum is in the +4 oxidation state.

### Step 3: Naming the ligands
The ligands in the complex are chlorido (from Cl). Since there are six chlorido ligands, we use the prefix "hexa-" to indicate the number of ligands. Therefore, we name the ligands as "hexachlorido".

### Step 4: Naming the metal
Since platinum is in the +4 oxidation state, we denote this in the name. The name of platinum in this oxidation state is "platinic".

### Step 5: Combine the names
The full name of the coordination complex is "hexachloridoplatinic".

### Step 6: Identify the type of compound
Since the compound contains hydrogen ions (H\(^+\)), it is classified as an acid. The IUPAC naming convention for coordination compounds that are acids includes the suffix "acid".

### Final Name
Combining all the information, the IUPAC name of \( H_2[PtCl_6] \) is:

**Hexachloridoplatinic(IV) acid**