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A: All square planar complexes can exhib...

A: All square planar complexes can exhibit geometrical isomerism.
R: In square planar complexes metal assumes `sp^(3)` hybridisation.

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1)

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2).

C

If Assertion is true statement but Reason is false, then mark (3).

D

If both Assertion and Reason are false statements, then mark (4)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion and the reason provided: ### Step 1: Analyze the Assertion The assertion states: "All square planar complexes can exhibit geometrical isomerism." - **Geometrical Isomerism**: This type of isomerism occurs when compounds have the same formula but different spatial arrangements of atoms. - **Square Planar Complexes**: Square planar complexes can exhibit geometrical isomerism, but not all square planar complexes do. - **Types of Square Planar Complexes**: - Complexes of the type M-A2-B2 (where M is bonded to two A ligands and two B ligands) can exhibit geometrical isomerism. - Complexes of the type M-A-B-C-D (where M is bonded to four different ligands) can also exhibit geometrical isomerism. - However, complexes of the type M-A4 (four identical ligands) or M-A3B (three identical ligands and one different) do not exhibit geometrical isomerism. Thus, the assertion is **false** because not all square planar complexes exhibit geometrical isomerism. ### Step 2: Analyze the Reason The reason states: "In square planar complexes, metal assumes sp³ hybridization." - **Hybridization in Square Planar Complexes**: The correct hybridization for square planar complexes is **dsp²**, not sp³. - **sp³ Hybridization**: This hybridization leads to a tetrahedral geometry, which is not applicable to square planar complexes. Thus, the reason is also **false**. ### Conclusion Both the assertion and the reason are false. Therefore, the correct answer is option 4: "Both assertion and reason are false." ---
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