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A : CH(3)— BH — CH(2) can not show reson...

A : `CH_(3)— BH — CH_(2)` can not show resonance.
R : Boron and carbocation both are electron defficient species.

A

If both Assertion’ & Reason are true and the reason is the correct explanation of the assertion, then mark'(1).

B

If both Assertion. & Reason are true but the reason is not the correct explanation of the ’ assertion, then mark (2).

C

If Assertion is true statement but Reason is false, then mark (3). .

D

If both Assertion and-Reason are false statements, then mark (4)

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Borane is an electron deficient compound. It has only six valence eletons, so the boron atom lacks an octet. Acquiring an octet is the driving force for the unusual bonding structure found in boron compounds. As an electron deficient compound, BH_(3) is a strong electrophile, capable of adding to a double bond. This hydroboration of double bond is though to oC Cur in one step, with the boron atom adding to the less highly substituted end of the double bond. In transition state, the boron atom withdraws electrons from the pi bond and the carbon at theother end of the double bond acquires a partial positive charge. This positive charge is more stable on the more highly subsituted carbon atom. The second step is the oxidation of boron atom, removing it from carbon and replacing it with hydroxyl group by using H_(2)O_(2)//OH^(bar(..)) . The simultaneous addition of boron and hydrogen to the double bond leads to a syn addition. Oxidation of the trialkyl borane replaces boron with a hydroxyl group in the same stereochemical position. Thus, hydroboration of alkenen is an example of steropecific reaction, in which different steroisomers of starting compounds react to give different steroisomers of the product. CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH=CH_(2) underset((ii)H_(2)O_(2)//OH^(bar(..)))overset((i)BH_(3)//THF)rarrZ . Z is :

Borane is an electron deficient compound. It has only six valence eletons, so the boron atom lacks an octet. Acquiring an octet is the driving force for the unusual bonding structure found in boron compounds. As an electron deficient compound, BH_(3) is a strong electrophile, capable of adding to a double bond. This hydroboration of double bond is though to oC Cur in one step, with the boron atom adding to the less highly substituted end of the double bond. In transition state, the boron atom withdraws electrons from the pi bond and the carbon at theother end of the double bond acquires a partial positive charge. This positive charge is more stable on the more highly subsituted carbon atom. The second step is the oxidation of boron atom, removing it from carbon and replacing it with hydroxyl group by using H_(2)O_(2)//OH^(bar(..)) . The simultaneous addition of boron and hydrogen to the double bond leads to a syn addition. Oxidation of the trialkyl borane replaces boron with a hydroxyl group in the same stereochemical position. Thus, hydroboration of alkenen is an example of steropecific reaction, in which different steroisomers of starting compounds react to give different steroisomers of the product. CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH=CH_(2) underset((ii)H_(2)O_(2)//OH^(bar(..)))overset((i)BH_(3)//THF)rarrZ . Z is :

A : CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH=CH_(2) on hydroboration oxidation gives CH_(3)-underset(OH)underset(|)overset(CH_(3))overset(|)(C)-underset(CH_(3))underset(|)(CH)-CH_(3) as major product . R : It involves the formation of carbocation so undergoes rearrangement .

When 3-methylbutan-2-ol is treated with HBr, the following reaction takes place: CH_(3)-underset(CH_(3))underset("| ")("C ")H-underset(OH)underset("| ")("C")H-CH_(3)overset(HBr)rarr CH_(3)-overset(Br)overset("| ")underset(CH_(3))underset("| ")("C ")-CH_(2)-CH_(3) Give a mechanism for this reaction. (Hint : The secondary carbocation formed in step II rearranges to a more stable tertiary carbocation by a hydride ion shift from 3rd carbon atom.

R - CH_(2) - CH_(2) OH can be converted into RCH_(2) CH_(2) COOH . The correct sequence of the reagents is

CH_(3)COCH_(3) and CH_(3)CH_(2)CHO can be distinguished by :

How many of the following species can show resonance.