Oxidation of toluene with `CrO_(3)` in the presence of `(CH_(3)CO)_(2)O` gives a product A which on treatment with aq. NaOH produce

Options

A. `C_(6)H_(5)COONa`
B. 2, 4-diacetyl toluene
C. `C_(6)H_(5)CHO`
D. `(C_(6)H_(5)CO)_(2)O`

Answer

To solve the problem of the oxidation of toluene with CrO3 in the presence of (CH3CO)2O, we will follow these steps:

### Step 1: Identify the Reactants
- Toluene (C6H5CH3) is our starting material.
- The oxidizing agent is chromium trioxide (CrO3).
- The solvent is acetic anhydride, which is (CH3CO)2O.

### Step 2: Perform the Oxidation Reaction
- In the presence of CrO3 and (CH3CO)2O, toluene undergoes oxidation.
- The methyl group (-CH3) in toluene is oxidized to a carbonyl group (-C=O).
- The reaction leads to the formation of benzaldehyde (C6H5CHO) as the primary product.

### Step 3: Write the Reaction
- The reaction can be summarized as:
\[ C6H5CH3 + CrO3 \xrightarrow{(CH3CO)2O} C6H5CHO \]

### Step 4: Treatment with Aqueous NaOH
- The product benzaldehyde (C6H5CHO) is then treated with aqueous NaOH.
- Aqueous NaOH provides hydroxide ions (OH⁻) which can lead to the formation of a benzyl alcohol through a reaction known as hydrolysis.

### Step 5: Write the Final Product
- The hydrolysis of benzaldehyde in the presence of NaOH results in the formation of benzyl alcohol (C6H5CH2OH).
- The overall reaction can be summarized as:
\[ C6H5CHO + NaOH \rightarrow C6H5CH2OH \]

### Final Answer
The product formed after the oxidation of toluene with CrO3 in the presence of (CH3CO)2O, followed by treatment with aqueous NaOH, is benzyl alcohol (C6H5CH2OH).

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