A polypeptide on complete hydrolysis gives three amino acids. How many sequences are possible for A polypeptide on complete hydrolysis gives three amino acids. How many sequences are possible for that polypeptide?

Options

A. 1
B. 3
C. 6
D. 9

Answer

To determine how many sequences are possible for a polypeptide that yields three amino acids upon complete hydrolysis, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Number of Amino Acids**: The problem states that the polypeptide gives three amino acids upon hydrolysis. Let's denote these amino acids as A, B, and C.

2. **Understand Permutations**: The different sequences of amino acids in a polypeptide can be understood as permutations of the three amino acids. A permutation is an arrangement of all the members of a set into a sequence.

3. **Calculate the Total Permutations**: The formula for the number of permutations of n distinct objects is given by n!. Here, n is the number of amino acids. Since we have three distinct amino acids (A, B, and C), we calculate the permutations as follows:
\[ \text{Number of sequences} = 3! = 3 \times 2 \times 1 = 6 \]

4. **List the Possible Sequences**: The possible sequences of the three amino acids are:
- ABC
- ACB
- BAC
- BCA
- CAB
- CBA

5. **Conclusion**: Therefore, the total number of different sequences (or arrangements) of the polypeptide that can be formed from three amino acids is 6.

### Final Answer:
The number of sequences possible for the polypeptide is **6**.

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