There are four point charges placed at the vertices of a square of side, `a=1.4 m`. If `q_(1)=+18 nC,q_(2)=-24 nC,q_(3)+35nC and q_(4)=+16 nC`m then find the electric potential at the centre P of the square Assume the potential to be zero at infinity.

Explanation

The distance of the point P from each charge is `r= (a)/(sqrt(2)) = (1.4m)/(1.4) =1m`
`V=V_(1)+V_(2)+V_(3)+V_(4)`
`=(1)/(4piepsilon_(0))[(q_(1))/(r_(1))+(q_(2))/(r_(2))+q_(3)/(r_(3))+(q_(4))/(r_(4))]`
`=(1)/(4piepsilon) .(q_(1)+q_(2)+q_(3)+q_(4))/(r)`
`=(1)/(4piepsilon_(0)).((18-24+35+16)xx10^(-9)C)/(1m)`
`=(9xx10^(9))xx(45xx10^(-9))V`
=405 V.