A bullet of mass 2 g is having a charge of 2 `mu`C. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of 10 m/s ?

Explanation

Use the relation qV = `(1)/(2) mv^(2), ` Here, q = 2 ` xx 10^(-6)` coulomb , m = 2 `xx 10^(-3)` kg, v = 10 m/s
therefore V = `(mv^(2))/(2q) = (2xx 10^(-3) (10)^(2))/(2 xx 2xx 10^(-6)) = (10^(-1))/(2 xx10^(-6)) = 5 xx 10^(4) `volt = 50 kV