A parallel -plate capacitor is connected to a battery that maintains a constant potential difference V between the plates. If the plates are pulled away from each other, increasing their separation, does the magnitude of the charge on the plates (a) increase, (b) decrease, or (c ) remain the same ?

Explanation

To solve the problem, we need to analyze the behavior of a parallel-plate capacitor when the distance between its plates is increased while it remains connected to a battery that maintains a constant potential difference \( V \).

### Step-by-Step Solution:

1. **Understanding the Capacitor**:
A parallel-plate capacitor consists of two conductive plates separated by a distance \( D \). The capacitance \( C \) of a parallel-plate capacitor is given by the formula:
\[
C = \frac{A \epsilon_0}{D}
...