For the following arrangement, find the equivalent capacitance between A and B
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Explanation

Here the 3 `mu F , 4 mu F ` and `5mu F` capacifors are in series
`:. C_(eq) =((1)/(3)+(1)/(4)+(1)/(5))^(-1) = (60)/(12+20+15) =(60)/(47) mu F`
Now 2 `mu F ` and `(60)/(47) mu F ` are in parallel so we have
`C_(aq)=C_(1)+C_(2)=(154)/(47) muF`