A parallel plate capacitor of capacitance C has been charged, so that the potential difference between its plates is V. Now, the plates of this capacitor are connected to another uncharged capacitor of capacitance 2C. Find the common potential acquired by the system and loss of energy.

Explanation

To solve the problem of the parallel plate capacitor, we will follow these steps:

### Step 1: Understand the initial conditions
The initial capacitance of the first capacitor is \( C \) and it is charged to a potential difference \( V \). The initial charge \( Q \) on the capacitor can be calculated using the formula:
\[ Q = C \cdot V \]

...