An alpha particle ( charge `= +2e)` is accelerated from rest through a potential difference of 500 volts . Its final kinetic energy as

Options

A. 50 eV
B. 500 eV
C. 1000 eV
D. 2000 eV

Explanation

To find the final kinetic energy of an alpha particle that is accelerated through a potential difference of 500 volts, we can use the relationship between electric potential energy and kinetic energy. Here’s a step-by-step solution:

### Step 1: Understand the Charge of the Alpha Particle
An alpha particle has a charge of \( +2e \), where \( e \) is the elementary charge (\( e \approx 1.6 \times 10^{-19} \) coulombs). Thus, the charge of the alpha particle can be calculated as:
\[ Q = 2e = 2 \times 1.6 \times 10^{-19} \text{ C} = 3.2 \times 10^{-19} \text{ C} \]

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