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A parallel plate capcitor of capcitance ...

A parallel plate capcitor of capcitance 5 `muF` and plate separation 6 cm is connected to a 1 V battery and charged. A dielectric of dielectric constant 4 and thickness 4 cm is introduced between the plates of the capacitor. The additional charge that flows into the capacitor from the battery is

A

`2 mu` C

B

`3 mu` C

C

`5 mu ` C

D

`10 mu ` C

Text Solution

Verified by Experts

Answer (3)
New capacitance is `(epsilon_(0)A)/((d-t)+(t)/(K))=(5d)/((d-t)+(t)/(K))=10muF`
`because ` Old capacitance is `(epsilon_(0)A)/(d) = 5 mu` F
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